2(x-2)^2-8=2x-8

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Solution for 2(x-2)^2-8=2x-8 equation: 



2(x-2)^2-8=2x-8

We move all terms to the left:

2(x-2)^2-8-(2x-8)=0

We get rid of parentheses

2(x-2)^2-2x+8-8=0

We add all the numbers together, and all the variables

-2x+2(x-2)^2=0

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